suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Answer:
Idk too much brain hurt
Step-by-step explanation:
Answer:
The function goes to positive infinity as x approaches positive and negative infinity
Step-by-step explanation:
I'm not sure exactly what it is but it would be a negitive
Answer:
1. Degree= 6, trinomial
2. degree= 4, binomial
Step-by-step explanation:
1. The largest exponent is 6 making it the degree and there are three terms because (m^5n^2), (mn^2), (n^6).
2. Since (9a^2bc^2) has the more than 1 exponent, you add them and the degree is 4. There are two terms because (2a^3b), (9a^2bc^2).