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3 years ago

Solve for n. 6 + 2n = 10 n =

Mathematics

1 answer:

melisa1 [442]3 years ago

8 0

Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{6+2n = 10}$

$\tt{2n = 10-6}$

$\tt{2n = 4}$

$\tt{n = \dfrac{4}{2}}$

$\boxed{\tt{n=2}}$

Hope it helps :)

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What is equivalent to 69

solong [7]

60+9
3*23
6*11.5
34.5*2

6 0

3 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3>Correct Question :-</h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3>Given :- </h3>

We have AP, 

$\sf{ 2 , 14 ,.... 98 }$
AP is the arithmetic progression or a sequence of numbers in which succeeding number is differ from preceeding number by a common value.

<h3>Solution :-</h3>

We have an AP :- 2 , 14 .....98

Therefore,

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

Here,

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

Now, 

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago

one more than six times that number is 25. select the solution and graph that represents the original number

Brums [2.3K]

6n+1 = 25

subtract 1 from each side

6n+1-1 = 25-1

6n = 24

divide each side by 6

6n/6 = 24/6

n =4

6 0

3 years ago

Why does these expressions 2(30x-24), 3(20x-16), and 4(15x-12) have the same expansion?

MariettaO [177]

The expressions have the same expansion I'd say because the pairs 2 and 30, 3 and 20, and 4 and 15 because they are all equivalent to 60 because they are all factors of 60.

Same goes with the other pairs, because they are all equivalent to 48 because they are all factors of 48.

6 0

3 years ago

6d2+8d-5=0 <img src="https://tex.z-dn.net/?f=6d%20%20%7B%7D%5E%7B2%7D%20%20%20%2B%208d%20-%205%20%3D%200%20%5C%5C%20" id="Tex

FromTheMoon [43]

The answer is d= 1/4
hope this helps

5 0

3 years ago