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Likurg_2 [28]
4 years ago
7

Divide x^4 + 7 by x-3

Mathematics
2 answers:
Sergeu [11.5K]4 years ago
4 0

your answer would be:

x^3+3x^2+9x+27 with a remainder of 88

AnnyKZ [126]4 years ago
3 0

Answer:asdfsdf

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

Step-by-step explanation:

Divide x^4 + 7 by x-3

\frac{x^4+7}{x-3}

to divide this we use long division

WE use 0 for other terms that are not given

x^4 + 0x^3 + 0x^3 + 0x +7

                    x^3 + 3x^2 +9x +27

                 --------------------------------

  x-3             x^4 + 0x^3 + 0x^3 + 0x +7

                     x^4 -3x^3

                -------------------------------------------(subtract it)

                           3x^3   +0x^2

                           3x^3   - 9x^2

                -------------------------------------(subtract)

                                      9x^2 + 0x

                                       9x^2 - 27x

                            -----------------------------------(subtract)

                                                27x + 7

                                                 27x -81

                                -----------------------------(subtract)

                                                         88

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

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