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4 years ago

Divide x^4 + 7 by x-3

Mathematics

2 answers:

Sergeu [11.5K]4 years ago

4 0

your answer would be:

x^3+3x^2+9x+27 with a remainder of 88

AnnyKZ [126]4 years ago

3 0

Answer:asdfsdf

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

Step-by-step explanation:

Divide x^4 + 7 by x-3

$\frac{x^4+7}{x-3}$

to divide this we use long division

WE use 0 for other terms that are not given

x^4 + 0x^3 + 0x^3 + 0x +7

x^3 + 3x^2 +9x +27

--------------------------------

x-3 x^4 + 0x^3 + 0x^3 + 0x +7

x^4 -3x^3

-------------------------------------------(subtract it)

3x^3 +0x^2

3x^3 - 9x^2

-------------------------------------(subtract)

9x^2 + 0x

9x^2 - 27x

-----------------------------------(subtract)

27x + 7

27x -81

-----------------------------(subtract)

Quotient : x^3 + 3x^2 +9x +27

Remainder : 88

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From the question we can say that the Hexagon has three shapes inside it,

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