−3(2+4k)+7(2k−1) eqivalent expression

Mathematics

1 answer:

Alex17521 [72]3 years ago

6 0

Answer:

$\large\boxed{-3(2+4k)+7(2k-1)=2k-13}$

Step-by-step explanation:

$-3(2+4k)+7(2k-1)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-3)(2)+(-3)(4k)+(7)(2k)+(7)(-1)\\\\=-6-12k+14k-7\qquad\text{combine like terms}\\\\=(-12k+14k)+(-6-7)\\\\=2k-13$

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Find the equation of the line which passes through the point (1,2), and is perpendicular to the line with the equation y=−12x+5.

malfutka [58]

12y = x + 23

Step-by-step explanation:

y = −12x + 5
Perpendicular slopes are opposite reciprocals.
The original slope is −12
So the new perpendicular slope is 1/12.
We plug the point (1, 2) and the slope m = 1/12 into the slope intercept form of the equation y = mx + b

y = mx + b

2 = 1/12 * 1 + b

2 = 1/12 + b

b = 23/12