Question

−3(2+4k)+7(2k−1) eqivalent expression

Answer 1

Answer:

$\large\boxed{-3(2+4k)+7(2k-1)=2k-13}$

Step-by-step explanation:

$-3(2+4k)+7(2k-1)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-3)(2)+(-3)(4k)+(7)(2k)+(7)(-1)\\\\=-6-12k+14k-7\qquad\text{combine like terms}\\\\=(-12k+14k)+(-6-7)\\\\=2k-13$