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xxMikexx [17]
3 years ago
6

−3(2+4k)+7(2k−1) eqivalent expression

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

\large\boxed{-3(2+4k)+7(2k-1)=2k-13}

Step-by-step explanation:

-3(2+4k)+7(2k-1)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-3)(2)+(-3)(4k)+(7)(2k)+(7)(-1)\\\\=-6-12k+14k-7\qquad\text{combine like terms}\\\\=(-12k+14k)+(-6-7)\\\\=2k-13

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Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake
Kamila [148]

Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

Step-by-step explanation:

The reason given to go from :

2 (3x +4) = 56  to 6x + 8 = 56

is NOT "Multiplication Property of Equality" because one is not multiplying both sides of the equality by a number. The property that is being used is the Distributive Property on the left side of the equation in order to remove the grouping symbols (parenthesis) performing the implied multiplication of the external factor times each term of the binomial in parenthesis.

8 0
3 years ago
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saul85 [17]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Sociologists say that 85% of married women claim that their husband's mother is the biggest bone of contention in their marriage
hoa [83]

Answer:

(A) 0.377,

(B) 0.000,

(C) 0.953,

(D) 0.047

Step-by-step explanation:

We assume that having a bone of intention means not liking one's Mother-in-Law

(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377

(B) P(none of the six dislike their Mother-in-Law) =

(100% - 85%)^6 =

0.15^6 =

0.000

(C) P(at least 4 dislike their Mother-in-Law) =

P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =

C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =

0.953

(D) P(no more than 3 dislike their Mother-in-Law) =

P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =

C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =

(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =

0.047

3 0
2 years ago
Gary is buying a $1,250 computer on the installment plan you makes a down payment on of $150 she has to make monthly payments of
Nataliya [291]
1250-150=1100
2 1/2 years = 30 months
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3 0
3 years ago
Read 2 more answers
An electronic system has each of two different types of components in joint operation. Let X and Y denote the lengths of life, i
AURORKA [14]

Answer:

a

The average cost is E(C) = 66

b

The standard deviation of  cost is  \sigma  = 9.798

Step-by-step explanation:

From the question we are told that

          E(X) =  4

          E(Y) =  2

          E(X^2) =  24

           E(Y^2) =  8

The cost of replacing the two component is  C =  50 + 2 X + 4 Y

The variance   of X is mathematically represented as

           V(X) =  E(X^2) - [E(X)]^2

Substituting values  

              V[X] =  24 - 4^2

               V[X] =8

The variance  of Y is mathematically represented as

           V(Y) =  E(Y^2) - [E(Y)]^2

Substituting values  

              V[Y] =  8 - 2^2

               V[X] =4

The average of  replacing the two component is  

        E(C) =  2 * E(X)  + 4* E(Y)

substituting value

         E(C) =  50 + 2 * (4)  + 4* (2)

         E(C) = 66

The variance  of replacing the two component is  

        V(C) = V(50 + 2X +4Y)      Note: The variance of constant is zero

                                                                  and X and  Y are independent  

=>      V(C) =  2^2 * V(X) + 4^2 * V(Y)

substituting values

=>       V(C) =  4 * 8 +  16 * 4        

=>         V(C) =  32 + 64

=>         V(C) = 96

The standard deviation is

         \sigma  =  \sqrt{V(C)}  

substituting values

           \sigma  =  \sqrt{96}

           \sigma  = 9.798

6 0
2 years ago
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