Answer:
33.7 kg
Explanation:
Let's consider calcium phosphate Ca₃(PO₄)₂.
The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol and the molar mass of P is 30.97 g/mol. In 1 mole of Ca₃(PO₄)₂ (310.18 g) there are 2 × 30.97 g = 61.94 g of P. The mass of Ca₃(PO₄)₂ that contains 3.57 kg (3.57 × 10³ g) of P is:
3.57 × 10³ g × (310.18 g Ca₃(PO₄)₂/61.94 g P) = 1.79 × 10⁴ g Ca₃(PO₄)₂
A particular ore contains 53.1% calcium phosphate. The mass of the ore that contains 1.79 × 10⁴ g of Ca₃(PO₄)₂ is:
1.79 × 10⁴ g Ca₃(PO₄)₂ × (100 g Ore/ 53.1 g Ca₃(PO₄)₂) = 3.37 × 10⁴ g Ore = 33.7 kg Ore
They are alive because they are in ur body and they can't be dead because they have to work the organisms inside of u
Answer:
0.1 m C6H12O6 < 0.1 m NaCl < 0.1 m Cu(NO3)2 < 0.1 m Fe(NO3)3
Explanation:
Step 1: Data given
ΔTb = Kb*m*i
⇒with Kb = 0.512°C/m
⇒with m = molality
⇒with i = Van't hoff factor = the number of particles into which the solute dissociates
a. 0.1 m NaCl
⇒ molality = 0.1 molal
⇒ i(NaCl) = 2 ( dissociates in Na+ and Cl-)
0.1 * 2 = 0.2
b. 0.1 m Cu(NO3)2
⇒ molality = 0.1 molal
⇒ i(Cu(NO3)2) = 3 ( dissociates in Cu^2+ and 2NO3-)
0.1 * 3 = 0.3
c. 0.1 m C6H12O6
⇒ molality = 0.1 molal
⇒ i(C6H12O6) = 1 ( doesn't dissociate in water)
0.1 * 1 = 0.1
d. 0.1 m Fe(NO3)3
⇒ molality = 0.1 molal
⇒ i(Fe(NO3)3) = 4 ( dissociates in Fe^3+ and 3NO3-)
0.1 * 4 = 0.4
0.1 m C6H12O6 < 0.1 m NaCl < 0.1 m Cu(NO3)2 < 0.1 m Fe(NO3)3
Answer:
7.42 atm
Explanation:
The total pressure is just the sum of partial pressures:
2.15 + 4.62 + 0.65 = 7.42 atm
Answer:
4 sig figs
Explanation:
There are 4 because they are all # 1 or above.
0 has special rules on whether or not it is significant.
0 being between two other sig figs no matter how far apart makes it a sig fig.
example: 101 is 3 sig figs
0 that is at the end of a non decimal number are not significant.
example: 110 is 2 sig figs
0 that are after a decimal are significant as long as they after another sig fig.
example: 1.000 and .1000 are both 4 sig figs
extra examples:
110.01 is 5 sig figs
110.1 is 4 sig figs
.0001 is 1 sig figs
