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3 years ago

In living things what is the source of the carbon-14 that is used in radiocarbon dating

2 answers:

5 0

In living things, the source of the carbon-14 that is used in radiocarbon dating is carbon dioxide in the atmosphere.
Living things inhale oxygen, and exhale carbon dioxide into the atmosphere, which is why the air and atmosphere are so full of it.

snow_tiger [21]3 years ago

3 0

Answer: carbon dioxide in the atmosphere

<em>- Prodixy</em>

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Using the atomic masses and relative abundance of the isotopes of nitrogen given below, determine the average atomic mass of nit

masha68 [24]

<span>To calculate the average mass of the element, we take the summation of the product of the isotope mass and the percent abundance. In this case, it is 0.9963 * 14.003 amu + 0.0037* 15.00 amu. This is equal to an average mass of 14.00668889 amu.</span>

8 0

3 years ago

Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A

horsena [70]

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

$P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}$

$P_f = \dfrac{2.80*717+4.30*174}{717+174}$

$P_f = \dfrac{2007.6+748.2}{891}$

$P_f = \dfrac{2755.8}{891}$

$\mathbf{P_f =3.09 \ atm}$

4 0

3 years ago

Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.

algol13

Answer : The value of $\Delta G_{rxn}$ is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.1)^3}{(1.4)^2}$

$Q=3.375$

Now we have to calculate the value of $\Delta G_{rxn}$ .

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction = ?

$\Delta G_^o$ = standard Gibbs free energy = -28.0 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

$\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)$

$\Delta G_{rxn}=-24.9kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is -24.9 kJ/mol

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3 years ago

A particular chemical reaction absorbs energy. It is possible to say the reactants possessed a lower energy than the products. T

Harrizon [31]

i'm pretty sure its true

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3 years ago

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3 years ago