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Irina18 [472]
3 years ago
11

HELP ASAP!!!!!!!!!!! * worth 35 points + brainliest *

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Explanation:

According to Arrhenius concept:

A base is defined as a substance which donates hydroxide ions (OH^-).When they are dissolved water it gives out hydroxide ions.

BOH(aq)\rightarrow B^+(aq)+OH^-(aq)

For example sodium hydroxide pellets when dissolved in water gives sodium ions and hydroxide ions.

NaOH\rightarrow Na^+(aq)+OH^-(aq)

Properties of Arrhenius bases:

  • They slippery in touch
  • They are bitter in taste if ingested.
  • They turn litmus paper blue.
  • They react with acid to undergo neutralization reaction in which water and salt is formed.
  • They pH value is always greater than  7.

An acid is defined as a substance which donates hydronium ions (H_3O^+) .When they are dissolved water it gives out hydronium ion.

AH(aq)\rightarrow A^-(aq)+H_3O^+(aq)

Musya8 [376]3 years ago
6 0

Answer:

In chemistry, a base is a substance that is slippery to the touch and has a pH greater than 7. If you were to eat a base (which you should not do) it would have bitter to the taste. A perfect example of a base is soap - when you touch soap, it feels slippery. Have you ever accidentally tasted soap? You may notice that it has a bitter taste.

These are some physical characteristics of bases, but what about the theory behind the behavior of bases when they are in a solution? There are many theories from different scientists that describe a base. One Swedish scientist, named Svante Arrhenius, came up with the theory of a base in 1884. Svante Arrhenius' definition of a base is what we now refer to as an Arrhenius base.

An Arrhenius base is a substance that, when dissolved in an aqueous solution, increases the concentration of hydroxide, or OH-, ions in the solution. An aqueous solution is a solution that has water present in it. Let's imagine dissolving a basic substance in water. According to Svante Arrhenius, when a base dissolves in an aqueous solution, it dissociates into ions and releases hydroxide ions.

NaOH dissociates into sodium, Na+, and hydroxide, OH-, ions. Because the hydroxide ions are released in the aqueous solution, the hydroxide concentration increases; therefore, NaOH is an Arrhenius base.

Sodium hydroxide, when dissolved in an aqueous solution, releases hydroxide ions in the solution.

The water above the arrow means that the NaOH is added or combined with water and dissociates into sodium, a positive cation, and one or more negative hydroxide anions.

Explanation:

Hope this helps

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Can Magnesium hydroxide be used as the base for this titration? Why or why not? 5. Describe the procedure that you will follow t
kvasek [131]

Explanation:

A.

Yes

B.

2KHP + Mg(OH)2 = 2KOH + Mg(HP)2

KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

C.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

= (12*8) + (5*1) + 39 + (16*4)

= 204 g/mol

Number of moles = mass/molar mass

= 20.4/204

= 0.1 mol.

• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix

D.

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O

1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

= 0.00125 mol.

Molarity = number of moles/volume

= 0.00125/0.01

= 0.125 M of Ba(OH)2.

4 0
3 years ago
¿Cuál de las siguientes configuraciones globales corresponde a un elemento químico que se comporta como metal? 1 punto [He]2s2 2
yuradex [85]

Answer:

[Ne]3s2

Explanation:

ahora tenemos que mirar cada una de las configuraciones electrónicas de cada átomo de cerca antes de tomar una decisión.

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5 0
3 years ago
Can someone please help me i dont understand and im about to get a zero
enyata [817]
Is this a test or something else?
6 0
3 years ago
n an experiment, 39.26 mL of 0.1062 M NaOH solution was required to titrate 37.54 mL of \ v unknown acetic acid solution to a ph
olasank [31]

Answer:

Molarity: 0.111M

% (w/w): 0.666

Explanation:

The reaction of NaOH with acetic acid (CH₃COOH) is:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>where 1 mole of NaOH reacts per mole of acetic acid producing 1 mole of water and 1 mole of sodium acetate.</em>

As 39.26mL ≡ 0.03926L of 0.1062M are required to titrate the solution of acetic acid. Moles are:

0.03926L × (0.1062mol / L) = 4.169x10⁻³ moles of NaOH. As 1 mole of NaOH reacts per mole of acetic acid:

4.169x10⁻³ moles of CH₃COOH.

Molarity is defined as ratio between moles of substance and volume of solution in liters. Thus, molarity of acetic acid solution is:

4.169x10⁻³ moles of CH₃COOH / 0.03754L = <em>0.111M</em>

<em></em>

As molar mass of acetic acid is 60g/mol, 4.169x10⁻³ moles weights:

4.169x10⁻³ moles × (60g / mol) = <em>0.2501 g of acetic acid</em>

Now, assuming density of solution as 1.00g/mL, 37.54mL weights <em>37.54g</em>.

Thus, percent by weight is:

0.2501g CH₃COOH / 37.54g × 100 = <em>0.666% (w/w)</em>

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