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2 years ago

HELP ASAP!!!!!!!!!!! * worth 35 points + brainliest *

Chemistry

2 answers:

gizmo_the_mogwai [7]2 years ago

7 0

Explanation:

According to Arrhenius concept:

A base is defined as a substance which donates hydroxide ions $(OH^-)$ .When they are dissolved water it gives out hydroxide ions.

$BOH(aq)\rightarrow B^+(aq)+OH^-(aq)$

For example sodium hydroxide pellets when dissolved in water gives sodium ions and hydroxide ions.

$NaOH\rightarrow Na^+(aq)+OH^-(aq)$

Properties of Arrhenius bases:

They slippery in touch
They are bitter in taste if ingested.
They turn litmus paper blue.
They react with acid to undergo neutralization reaction in which water and salt is formed.
They pH value is always greater than 7.

An acid is defined as a substance which donates hydronium ions $(H_3O^+)$ .When they are dissolved water it gives out hydronium ion.

$AH(aq)\rightarrow A^-(aq)+H_3O^+(aq)$

Musya8 [376]2 years ago

6 0

Answer:

In chemistry, a base is a substance that is slippery to the touch and has a pH greater than 7. If you were to eat a base (which you should not do) it would have bitter to the taste. A perfect example of a base is soap - when you touch soap, it feels slippery. Have you ever accidentally tasted soap? You may notice that it has a bitter taste.

These are some physical characteristics of bases, but what about the theory behind the behavior of bases when they are in a solution? There are many theories from different scientists that describe a base. One Swedish scientist, named Svante Arrhenius, came up with the theory of a base in 1884. Svante Arrhenius' definition of a base is what we now refer to as an Arrhenius base.

An Arrhenius base is a substance that, when dissolved in an aqueous solution, increases the concentration of hydroxide, or OH-, ions in the solution. An aqueous solution is a solution that has water present in it. Let's imagine dissolving a basic substance in water. According to Svante Arrhenius, when a base dissolves in an aqueous solution, it dissociates into ions and releases hydroxide ions.

NaOH dissociates into sodium, Na+, and hydroxide, OH-, ions. Because the hydroxide ions are released in the aqueous solution, the hydroxide concentration increases; therefore, NaOH is an Arrhenius base.

Sodium hydroxide, when dissolved in an aqueous solution, releases hydroxide ions in the solution.

The water above the arrow means that the NaOH is added or combined with water and dissociates into sodium, a positive cation, and one or more negative hydroxide anions.

Explanation:

Hope this helps

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The boiling point of water is 100ºC. The boiling point of acetone is 56ºC. Which statement about distilling a mixture of acetone

Anika [276]

Answer:

I think Acetone will be captured and cooled.

Explanation:

Distillation is a method of separation based on the difference in boiling point of two liquids.

The liquid that has a lower boiling point is first separated from the mixture. It vaporizes, cooled and collected before the liquid that has a higher boiling point.

In this case, acetone is captured and cooled before water since it has a boiling point of 56ºC and water has a boiling point of 100ºC.

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1 year ago

in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat

Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0

2 years ago

A fossilized leaf contains 24% of its normal amount of carbon 14. how old is the fossil (to the nearest year)? use 5600 years as

sergij07 [2.7K]

The Half life is the time taken for a radioisotope or a radioactive substance to decay by half its original amount. The half life of carbon 14 is 5600 years.
Original mass is 100%
Remaining amount is 24%
Therefore; 0.24 = 1 × (1/2)^n
n = log 0.24/log 0.5
= 2.06
therefore, the age of the fossil is 5600×2.06
= 11529.8
≈ 11529 years

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3 years ago

How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif

Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is $7.5\times 10^{-9}mol$

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is $6.022\times 10^{23}$

We are given:

Number of formula units of $Sr(HCO_3)_2=4.55\times 10^{15}$

As, $6.022\times 10^{23}$ number of formula units are contained in 1 mole of a substance.

So, $4.55\times 10^{15}$ number of formula units will be contained in = $\frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol$ of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is $7.5\times 10^{-9}mol$

5 0

2 years ago

one reaction that produces hydrogen gas can be represented by the unbalanced chemical equation Mg(s)+HCI(aq) -> MgCI(aq)+H2(g

Sonbull [250]

<h3>Answer:</h3>

128 g HCl

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Reaction Mole Ratios
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg (s) + HCl (aq) → MgCl (aq) + H₂ (g)

↓

[RxN - Balanced] 2Mg (s) + 2HCl (aq) → 2MgCl (aq) + H₂ (g)

[Given] 3.25 mol Mg

[Solve] x g HCl

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol HCl

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

<u>Step 3: Stoich</u>

[S - DA] Set up: $\displaystyle 3.25 \ mol \ Mg(\frac{2 \ mol \ HCl}{2 \ mol \ Mg})(\frac{36.46 \ g \ HCl}{1 \ mol \ HCl})$
[S - DA] Multiply/Divide [Cancel out units]: $\displaystyle 127.61 \ g \ HCl$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

127.61 g HCl ≈ 128 g HCl

3 0

2 years ago