Question

A gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from blank L to 0.492L and the temperature changes from 643K to 525K

Answer 1

P₁ = 39.1 bar  

V₁ = ?  

T₁ = 643 K  

P₂ = 87.0 bar  

V₂ = 0.492 L  

T₂ = 515 K  

P₂ = ?  

P₁V₁/T₁ = P₂V₂/T₂  

V₁ = P₂V₂T₁/P₁T₂ = (87.0)(0.492)(643) / (39.1)(515) = 1.37 L

Answer 2

Answer: -

1.34 L

Explanation: -

Initial Pressure P 1 = 39.1 bar

Initial Temperature T 1 = 643 K

Let the initial volume be V 1.

Final pressure P 2 = 87.0 bar

Final temperature T 2 = 525 K.

Final volume V 2 = 0.492 L

Using the equation

$\frac{P1 V 1}{T1} = \frac{P 2 V 2}{T2}$

$V 1 = \frac{P2 V2 T1}{P 1 T2}$

Plugging in the values

We have

V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)

= 1.34 L

Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K