Your answer would be “a”.
In order to receive a positive solution in the following equation, you must include a double negative to have them cancel each other out and come up with a positive value. Sorry if this is confusing it’s easier to explain this process in person rather than online but I hope this helps anyways :)
100(whole class is 100%) / 6060(number of students total) = any random student chance
0.0165
A) for democrats multiply chance of any random student with number of democrats
0.0165×4040=66.66666...
B) for business majors, multiply that chance with number of business majors
0.0165×1010=16.66666...
C) for both business major and democrat multiply chance with numbers of students who are both
0.0165×33=0.544...
The probability of winning is 4/13.
These two events are not mutually exclusive; this means they can happen at the same time. For two events that are not mutually exclusive,
P(A or B) = P(A) + P(B) - P(A and B)
This gives us
P(spades or Ace) = P(spades) + P(Ace) - P(spades and Ace)
There are 13 spades out of 52 cards.
There are 4 aces out of 52 cards.
There is 1 card that is a spade and an ace out of 52 cards.
13/52 + 4/52 - 1/52 = 16/52 = 4/13
No, this is because right angles can also be formed
Answer:
Step-by-step explanation:
Evaluate 6(5-(6-5)-3) = 6(5-1-3) {first solve innermost bracket}
= 6* (5-4) = 6*1 =6
