Answer:
{ Pythagorean Theorem}
{Division property of Equality}
sin 0=a/c{definition of sin0)
cos0=b/c{definition of cos0)
{Substitution}
Step-by-step explanation:
A) 110/21 = 5 5/21
B) 10
C) 21/4 = 5 1/4
D) 16/5 = 3 1/5
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Wait is the middle school.