Which of the following is an example of a health short term goal

Brainliest if correct. pls help. improper answer will lead to automatic report. will not report if wrong. 25+pts

RideAnS [48]

Answer:

x = 1.56

Step-by-step explanation:

so what you have to do is isolate the variable by dividing each side by factors that don't contain the variable.

8 0

2 years ago

Read 2 more answers

Jill and Marcy go to an ice cream store where they have the option of getting a smoothie in either a cylindrical or rectangular

k0ka [10]

Answer: Jill got the larger smoothie and its volume is 1609.14 cubic cm.

Step-by-step explanation:

Since we have given that

Jill purchased the cylindrical container.

Height of container = 8 cm

Radius = 8 cm

So, volume of cylindrical container would be

$\pi r^2h\\\\=\dfrac{22}{7}\times 8\times 8\times 8\\\\=1609.14\ cm^3$

Marcy purchased the rectangular container.

Height of container = 8 cm

Width = 8 cm

Length = 8 cm

so, volume of rectangular container would be

$l\times b\times h\\\\=8\times 8\times 8\\\\=512\ cm^3$

Hence, Jill got the larger smoothie and its volume is 1609.14 cubic cm.

3 0

2 years ago

According to the fundamental theorem of algebra which polynomial function has exactly 8 roots? A.F(x)=(3x^2-4x-5)(2x^6-5) B.f(x)

choli [55]

I think it’s a because I added from the therum

3 0

2 years ago

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

3 years ago

Candidates running for office are handing out items to voters. Every 6th voter gets a button. Every 7th voter gets a sticker.

e-lub [12.9K]

The computation shows that the voter is the first to receive both items is A. the 42nd voter.

<h3>How to compute the value?</h3>

From the information, the candidates running for office are handing out items to voters as every 6th voter gets a button while every 7th voter gets a sticker.

Therefore, it should be noted that the least common multiple of both 6 and 7 is 42. Therefore, the voter is the first to receive both items is the 42nd voter.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

6 0

1 year ago