Answer:
384 m³
Step-by-step explanation:
Let the dimension of box a be l,b, and h.
ATQ,
lbh = 48 .....(1)
If we double the dimension of box A, we get box B whose new dimensions will be 2l,2b and 2h.
Let V be the volume of box B.
V = (2l)(2b)(2h)
V = 8(lbh)
= 8(48) [from equation (1)]
= 384 m³
Hence, the volume of the box B is 384 m³.
Answer:
x = 3 ± 
or
x = 3 + , x = 3 -
Step-by-step explanation:
given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40
So, we plug in 40 for f(x) in the 1st equation and solve for x. (Aim to got x on its own)
40 = 2 (x - 3)^2 - 8
+ 8 + 8
-----------------------------
48 = 2 (x - 3)^2
/2 /2
-----------------------------
24 = (x - 3)^2
square root both sides
--------------------
= x - 3
x = 3 ±
25(25) = 625
625/60 ≈ 10.4166
Or when rounded to the nearest hundredth, 10.42
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
