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densk [106]
3 years ago
7

Root of 2x plus 1/3 square

Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

Here's the answer. Have a good day

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Using power series, solve the LDE: (2x^2 + 1) y" + 2xy' - 4x² y = 0 --- - -- -
sattari [20]

We're looking for a solution of the form

y=\displaystyle\sum_{n\ge0}a_nx^n

with derivatives

y'=\displaystyle\sum_{n\ge0}(n+1)a_{n+1}x^n

y''=\displaystyle\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n

Substituting these into the ODE gives

\displaystyle\sum_{n\ge0}\left(\bigg(2(n+2)(n+1)a_{n+2}-4a_n\bigg)x^{n+2}+2(n+1)a_{n+1}x^{n+1}+(n+2)(n+1)a_{n+2}x^n\right)=0

Shifting indices to get each term in the summand to start at the same power of x and pulling the first few terms of the resulting shifted series as needed gives

2a_2+(2a_1+6a_3)x+\displaystyle\sum_{n\ge2}\bigg((n+2)(n+1)a_{n+2}+2n^2a_n-4a_{n-2}\bigg)x^n=0

Then the coefficients in the series solution are given according to the recurrence

\begin{cases}a_0=y(0)\\\\a_1=y'(0)\\\\a_2=0\\\\2a_1+6a_3=0\implies a_3=-\dfrac{a_1}3\\\\a_n=\dfrac{-2(n-2)^2a_{n-2}+4a_{n-4}}{n(n-1)}&\text{for }n\ge4\end{cases}

Given the complexity of this recursive definition, it's unlikely that you'll be able to find an exact solution to this recurrence. (You're welcome to try. I've learned this the hard way on scratch paper.) So instead of trying to do that, you can compute the first few coefficients to find an approximate solution. I got, assuming initial values of y(0)=y'(0)=1, a degree-8 approximation of

y(x)\approx1+x-\dfrac{x^3}3+\dfrac{x^4}3+\dfrac{x^5}2-\dfrac{16x^6}{45}-\dfrac{79x^7}{125}+\dfrac{101x^8}{210}

Attached are plots of the exact (blue) and series (orange) solutions with increasing degree (3, 4, 5, and 65) and the aforementioned initial values to demonstrate that the series solution converges to the exact one (over whichever interval the series converges, that is).

5 0
3 years ago
Does a quadrilaterals have 4 corners
horrorfan [7]
A quadrilateral does have 4 side
3 0
3 years ago
Is 36/54 the same as 48/72?
skad [1K]
\frac{36}{54} = \frac{18\times 2}{18\times 3} = \frac{2}{3}

\frac{48}{72} = \frac{24\times 2}{24\times 3}= \frac{2}{3}

So, yes! Both fractions are equivalent.
7 0
3 years ago
Read 2 more answers
A parabolic microphone used on the sidelines of a professional football game uses a reflective dish 24 inches wide and 6 inches
Strike441 [17]
The answer is a.
When you are solving problems like this you would use the equation y^2=4ax. The x and Y would be the coordinates. Based on the equation you have given the coordinates would be (6,12) and (6,-12), (24 is split up evenly between the y-axis).  
Then we go on to solve the equation by plugging in the numbers 12^2=4a(6)
144=24a
144/24=24a/24
6=a
5 0
3 years ago
2+2 ajjdbnmsfnksfnbdnsdbcs,mdv bn,zdb xzvndzsmbznx,vsdanvbf
avanturin [10]

Answer:

I belive the answer would be 4ajjdbnmsfnksfnbdnsdbcs,mdv bn,zdb xzvndzsmbznx,vsdanvbf.  : ) ahaha

6 0
3 years ago
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