D=60. multiply both sides of the equation by 4 since it’s a factor, giving you 2d-20-d=40. since there are like terms with d, collect them to get d-20=40 and move 20 to the right and change it’s sign. that will give you d=40+20, then calculate to get d=60. hope this helped! :)
F(x) = x²-4x-5, quadratic function,
Domain (the values if x) is all real numbers.
To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up. Minimum value of y =-9
Range(the values of y) is [-9, ∞)
Answer:
√2/2
Step-by-step explanation:
If sinP = √2/2,
Rationalize;
√2/2
= √2/2,*√2/√2
√4/2√2
= 2/2√2
= 1/√2
Hence sinP = 1/√2
Take sin inverse of both sies
arcsinP = arcsin1/√2
P = 45 degrees
cos P = Cos 45
= 1/√2
= 1/√2 * √2/√2
= √2/2
Hence the value of cosP is √2/2
Answer:
5 x 2 -3 = 7
Step-by-step explanation:
i mean.... thats all
