Answer:
x=1 y =15
Step-by-step explanation:
hopefully correct
-5x-2y=13 (i)
3x-y=12
-y=12-3x
y=-12+3x (ii)
substitute ii into i
-5x-2(-12+3x)=13
-5x +24-6x=13
-11x=-11
x=1
substitute x into ii
y=-12+3(1)
y=15
.
. . x=1 and y =15
Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:
its C
Step-by-step explanation:
Answer:350,000
Step-by-step explanation:
Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Step-by-step explanation:
Let us consider the general linear equation
Y = MX + C
On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).
Slope = ( 0 - -1)/( 2- 0) = 1/2
When x = 0, Y = -1
Substitutes both into general linear equation
-1 = 1/2(0) + C
C = -1
The equations for the coordinate is therefore
Y = 1/2X - 1
Let's check the equations one after the other
y = negative one-half x minus 1
Y = -1/2X - 1
y = negative one-half x + 1
Y = -1/2X + 1
y = one-half x minus 1
Y = 1/2X - 1
y = one-half x + 1
Y = 1/2X + 1
It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.