The question GIVES us an equation:
V₀ = √(v² - 64h) .
It TELLS us that v should be 100 ft/sec and h is 150 ft.
All we have to do is plug the numbers into the equation,
and then do the arithmetic to find V₀.
There's not even any Physics to do. Only arithmetic.
V₀ = √(v² - 64h)
v = 100
h = 150
V₀ = √(100² - 64·150)
V₀ = √(10,000 - 9,600)
V₀ = √400
V₀ = 20 ft per sec .
Answer:
1000000 = 1 MLN CODES
Step-by-step explanation:
According the terms of the problems the code has 6 digits or has 6 positions.
At 1st position any of 10 digits (0,1,2,3,4,5,6,7,8 or 9 ) can put
The digits can repeated, so at position 2 any of 10 difits can put.
At position 3 again any of 10 digits can put and similarly for each of next positions can be put any of 10 digits.
So each position of the code has 10 possible variants.
To find the total number of possible codes we have to multiply the number of variants for each position to each other.
N=10*10*10*10*10*10= 10^6=1 000 000
Cubes and then three dimensional
