Answer:
Option B is correct = 
Step-by-step explanation:
<u>The complete question is:</u> Which of the following options have the same value as 30% of 81?
Group of choices is:
(A) 
(B) 
(C) 
(D) 
(E)
Now, the expression given to us is 30% of 81.
Simplifying the above expression we get;
30% of 81 =
=
= 
Now, we will solve each of the given options and then see which option matches with our calculation.
Option (A) is given;
= 
This doesn't match with our answer, so this option is not correct.
Option (B) is given;
<u><em>This matches with our answer, so this option is correct.</em></u>
Option (C) is given;
This doesn't match with our answer, so this option is not correct.
Option (D) is given;
= 
This doesn't match with our answer, so this option is not correct.
Option (E) is given;
This doesn't match with our answer, so this option is not correct.
Answer:
Step-by-step explanation:
Let the no of cars be x and no of buses be y.
x + y = 60 -> y = 60 - x
6x + 30y = 600
with the available equations let us calculate the values of x and y.
6x + 30 * (60-x) = 600
6x + 1800 - 30x = 600
24x = 1200
x cars = 50
y buses = 10
maximum profit = 50 * 2.5 + 10 * 7.5 = $200
Your dividing number for both is by 8. Since 8 hours divided by 8 equals 1. You will do the same to the top and get an answer of 25 miles!!
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
You can multiply the fraction by any number you want so you gonna have an other fraction that is equal to your fraction like : 3 × 2 / 5 × 2 = 6 /10 so 3/5 = 6/10 :)))
i hope this be helpful
have a nice day