Answer:
Option D. 12
Step-by-step explanation:
To obtain the answer to the question, let us form a frequency table for the class.
This is illustrated below:
Class >>>>>>>>>>>>> Frequency
0.320 – 0.329 >>>>> 1
0.330 – 0.339 >>>>> 14
0.340 – 0.349 >>>>> 12
0.350 – 0.359 >>>>> 2
0.360 – 0.369 >>>>> 1
From the table illustrated above, class 0.340 – 0.349 have 12 values.
Answer:
x > 36 in
Step-by-step explanation:
Let x = the width of the picture frame.
Then x + 6 = the length of the frame.
The formula for the perimeter P of a rectangle is'
P = 2l + 2w.
So, the condition is
2l + 2w > 156
2(x + 6) + 2x > 156 Distribute the 2
2x + 12 + 2x > 156 Combine like terms
4x + 12 > 156 Subtract 12 from each side
4x > 144 Divide each side by 4
x > 36
The perimeter of the picture frame will be greater than 156 in if x > 36 in.
You can't put it in simplest form 13 can't go lower evenly
Uuuuh...
<span>c + 4 = t
t + 2 = 2c
c + 4 = 2c – 2
c = 2
t = 6
</span>
or
<span>
c = t - 4....................................(1) </span>
<span>in 2 years we have: </span>
<span>t + 2 = 2(c + 2) </span>
<span>i.........e......... t + 2 = 2c + 4 </span>
<span>=&gt; t - 2c = 2...........................(2) </span>
<span>(1) into (2) for c gives: </span>
<span>t - 2(t - 4) = 2 </span>
<span>i.........e......... 8 - t = 2 </span>
<span>so, t = 6 and c = 2 </span>
<span>therefore, terrill is 6 and cranston is 2 </span>
<span>and, in 2 years time they shall be 8 and 4....................................i..... terrill being twice cranston's age </span>
i lost myself the first time i solved it
