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DanielleElmas [232]
4 years ago
14

PLS HELP ME ASAP FOR 1, 2, AND 3! (FIND X OR FIND THE SQUARE ROOT IF POSSIBBLE (?)

Mathematics
1 answer:
Anvisha [2.4K]4 years ago
8 0
1. You basically have the right idea.
.. x +3 = ±4
.. x = {-7, 1}

2. v^2 +2v = 8
.. (v +1)^2 = 9
.. v = -1 ±3 = {-4, 2}

3. x^2 -10x = 11
.. (x -5)^2 = 36
.. x = 5 ±6 = {-1, 11}

4. p^2 -8p = -15
.. (p -4)^2 = 1
.. p = 4 ±1 = {3, 5}
You might be interested in
quadritlateral with two separate pairs of equal sides and my four sides cannot be equal, my equal sides are next to each other.
Anarel [89]
Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.

3 0
3 years ago
Follow the steps to solve for the variable in this two-step equation:
Ratling [72]

Answer:

x=2

Step-by-step explanation

5x-10=0

fist add 10 to both sides to cancel the -10 on the left side

5x=10

then divide both sides to cancel the 5 in front of the x and to get the x all by itself

x=2

and then you have your answer!

8 0
3 years ago
Please answer this for me.
Nastasia [14]

Answer:

(x + 5)**2 + (y + 2)**2 = 25

Step-by-step explanation:

We know that the general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius. The graph shows the center at (-5, -2), and the radius of 5. So plugging this in

(x - -5)**2 + (y - - 2)**2 = 5**2

(x + 5)**2 + (y + 2)**2 = 25

6 0
3 years ago
The measures of the obtuse angles in the isosceles trapezoid are five more than four times the measures of the acute angles. Wri
emmainna [20.7K]

Answer:

a. i. x + y = 180  (1) and  x - 4y = 5   (2)

ii. The two acute angles are 35° each and the two obtuse angles are 145° each.

Step-by-step explanation:

a. The measures of the obtuse angles in the isosceles trapezoid are five more than four times the measures of the acute angles. Write and solve a system of equations to find the measures of all the angles.

i. Write a system of equations to find the measures of all the angles.

Let x be the obtuse angles and y be the acute angles.

Since we have two obtuse angles at the top of the isosceles trapezoid and two acute angles at the bottom of the isosceles trapezoid, and also, since the sum of angles in a quadrilateral is 360, we have

2x + 2y = 360

x + y = 180  (1)

Its is also given that the measures of the obtuse angles in the isosceles trapezoid are five more than four times the measures of the acute angles.

So, x = 4y + 5   (2)

x - 4y = 5   (2)

So, our system of equations are

x + y = 180  (1) and  x - 4y = 5   (2)

ii. Solve a system of equations to find the measures of all the angles.

Since

x + y = 180  (1) and  x - 4y = 5   (2)

Subtracting (2) from (1), we have

x + y = 180  (1)

-

x - 4y = 5   (2)

5y = 175

dividing both sides by 5, we have

y = 175/5

y = 35°

From (1), x = 180° - y = 180° - 35° = 145°

So, the two acute angles are 35° each and the two obtuse angles are 145° each.

4 0
3 years ago
Simplify.
natima [27]
Its 2y+7z hope dis helps
5 0
3 years ago
Read 2 more answers
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