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aksik [14]
3 years ago
10

A Professor at a University sent his phone number in a disorderly manner to his students. The disordered phone number was 640011

28454.
To know his real phone number, he gave the student the following conditions:

1. Eight (8) must come between two zeros (0's).

2.The first number after the first condition is met must not be an odd number and it must be greater than 5.

3. The seventh number must be 1.

4. The fifth and sixth numbers must be two numbers whose difference is 1 and the bigger number must come first.

5. The fifth and sixth numbers are greater than 2.

6. The ninth and tenth numbers are the same.

7. The eighth number is greater than the last number.

8. The phone number must be 11 digits.

What was the Professor's real phone number?​
Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

I found 608054144112

If the number isn't found by the given condition, write a variable to advance. but it is comfortable to solve if you follow them one by one

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Anit [1.1K]
There are two solutions.
.. (3, 2)
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If you're choosing possibilities from a list, trying them in the equations usually gives quick results.

4 0
3 years ago
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Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
2 years ago
The Powerball lottery is decided every Wednesday and Saturday night by drawing five white balls out of a drum with 69 balls and
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^{69}C_5\\\\=11,238,513

And

b) Number of possible ways of different winning Poweball tickets are there would be

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7 0
2 years ago
Suppose that A, B, and C are invertible matrices of the same
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Answer:

Step-by-step explanation:

Given that t A, B, and C are invertible matrices of the same

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to pr that  ( ABC) (C^{-1}B^{-1}A^{-1})=e

LS=( AB(C (C^{-1})B^{-1}A^{-1})\\=ABIB^{-1}A^{-1})\\=A(BB^{-1})A^{-1})\\=AA^{-1})\\=I

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8 0
3 years ago
What is the value of 5 in 356,039,763
frosja888 [35]
Well, we know the last three numbers are:

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The next set is:

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And finally:

6 (millions)
5 (ten millions)
6 (hundred millions)

So we know that 5 is in ten millions.



7 0
3 years ago
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