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svetlana [45]
3 years ago
12

What is the nearest tenth of 28cm

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

30cm

Step-by-step explanation:

"5 or above, give it shove. 4 or below, let it go." The number is the tenth's place is 2(since this isn't a decimal), and you need to round it by the number to it's right: which is 8. Since 8 is greater than 5, you change the 2 to a 3 and the 8 becomes a 0.


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Answer:$373.50

Step-by-step explanation:

$498.00 divided by 40 is 12.45

12.45 times 30 is $373.50

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the selling price would be 60.75

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TiliK225 [7]

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Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

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Hence,

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3 0
3 years ago
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castortr0y [4]

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