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Diano4ka-milaya [45]

2 years ago

9

Find the principal which earns birr 115.38 in 8 years at

a1" title="4\frac{1}{2}" alt="4\frac{1}{2}" align="absmiddle" class="latex-formula">% per amount

1 answer:

horsena [70]2 years ago

4 0

Answer:

115.38 divided by 8 equals 14.4225

Step-by-step explanation:

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I need help please!

den301095 [7]

9514 1404 393

Answer:

f(g(x)) = 2/(x^2 +4x)

Step-by-step explanation:

$(f\circ g)(x)=f(g(x))\\\\(f\circ g)(x)=f(x+2)=\dfrac{2}{(x+2)^2-4}\\\\(f\circ g)(x)=\dfrac{2}{x^2+4x+4-4}\\\\\boxed{(f\circ g)(x)=\dfrac{2}{x^2+4x}}$

3 0

2 years ago

Eddy is going to multiply a whole number greater than zero by 10. Which sentence is true about the product?

Semmy [17]

The sentence that is true should have something to do with that 10 multiplied by any number is the number being multiplied by 10 with a zero at the end.
All numbers greater than 0 and smaller than 10 multiplied by 10 and their products are
1×10=10
2×10=20
3×10=30
4×10=40
5×10=50
6×10=60
7×10=70
8×10=80
9×10=90
I hope this helps

6 0

3 years ago

Read 2 more answers

What are three comparisons you can make for the numbers 150, 300, and 450?

DedPeter [7]

They are 150 apart
all 3 are even
and they are all in the hundreds

3 0

3 years ago

Yuri [45]

To do this, lets identify the slope and the y-intercept.

y = mx + b
y = -1/2x - 2

The slope is -1/2 and -2 is the intercept.

So, it is the 3rd one.

Hope this helps!

3 0

2 years ago

Read 2 more answers

If a die is rolled 40 times, there are 640 different sequences possible. The following question asks how many of these sequences

RideAnS [48]

Answer:

0.1433

Step-by-step explanation:

<h3><u>All possibilities:</u></h3>

The total number of different sequences in 40 rolls of a die is $6^{40}$

<h3><u>Exactly five 1s in 40 rolls:</u></h3>

The 1s may occur at any 5 rolls among 40. The number of ways of exactly five 1s occuring is therefore, equivalent to number of ways of selecting 5 fruits from 40 distinct fruits which is ⁴⁰C₅ ways. These 5 rolls have a fixed outcome <u>1</u>. Other 35 rolls each have 5 possible outcomes : <u>2</u> or <u>3</u> or <u>4</u> or <u>5</u> or <u>6</u>. So, the number of possible sequences of outcomes on other 35 rolls of the die is $5^{35}$ .

⇒The total number of different sequences having exactly five 1s in 40 rolls of a die is (⁴⁰C₅)×( $5^{35}$ )

∴The fraction of the total number of sequences having exactly five 1s is $\frac{(⁴⁰C₅)×([tex]5^{35}$ )}{ $6^{40}$ }[/tex] ≈ <u>0.1433</u>

4 0

3 years ago