Question

A box is filled with 2 blue cards, 4 brown cards, and 6 yellow cards. A card is chosen at random from a box. What is the probability that the card is not brown?

Answer 1

Answer:

Therefore the probability that the card is not brown is $\frac12$.

Step-by-step explanation:

Probability: Probability is the ratio of the favorable outcome to the total outcome.

$Probability =\frac{\textrm{Favorable outcome}}{\textrm {Total outcome}}$

Given that, a box contains  2 cards blue in color , 4 cards brown in color and 6 cards yellow in color.

Total number of cards= (2+4+6)=12

∴P(getting a brown card)

$=\frac{\textrm{No. of brown card}}{\textrm{Total no. of card}}$

$=\frac{6}{12}$

$=\frac12$

∴P(not getting a brown card)

=1 - P(getting a brown card)

$=1-\frac12$

$=\frac12$

Therefore the probability that the card is not brown is $\frac12$.

Answer 2

Answer:

2/3

Step-by-step explanation:

hey there!

so our first step is to find the total number of cards

2+4+6=12

now we have to find the number of cards that are not brown

2+6=8

the probability would be 8/12

this can be simplified to 2/3 by dividing the numerator and denominator by 4

2/3 is also equal to 66.67%