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lora16 [44]
2 years ago
8

Are mixtures pure substances that cannot be changed into smaller substances?

Biology
1 answer:
Gwar [14]2 years ago
3 0
No. A mixture is a combination of two or more other substances.
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What is the purpose of a dichotomous key of the sort you might find in a field guide?
Serjik [45]

Good morning!! The purpose of both a dichotomous key and a field guide's purpose is to identify organisms. The only difference between the two is the a dichotomous key just uses descriptions to identify the animal with no pictures, but a field guide uses pictures to identify the organism. Another thing that separates the two is that the dichotomous key gives questions/descriptions that describe the organism, whereas the field guide uses a brief description of the animal. Hope I helped!!

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2 years ago
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What part does chlorophyll play in photosynthesis?
lara [203]

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it captures the sun's energy

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PLS ANSWER QUICK!
Colt1911 [192]

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2 years ago
Infections arising from the periapical region of the mandibular first premolars perforate through the lingual cortex to theA- Pt
Reika [66]

Answer:

The correct answer is option C- "Sublingual space".

Explanation:

If an infection perforate from he mandibular first premolars through the lingual cortex, it is very likely that it continues is way into the sublingual space. The infections located at the sublingual space are often bacterial infections that comes precisely from the floor of the mouth. If an infection goes into the lingual cortex, it will often go to the tissue under the tongue at the sublingual space.

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3 years ago
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In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
2 years ago
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