<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
They will see each other every 30 days but won't every 15 days
B. Sandwich costs $7.70 and the soda costs $2.20
Answer: A
Step-by-step explanation: Hope this help :D
Answer:
(-5,24)
Step-by-step explanation:
2f+3g-h
first we substitute in the numbers
2(-3)+3(1)-2
-6+3-2
-3-2
-5
Then again
2(5)+3(4)-(-2)
10+12+2
22+2
24
hope this helps!:)
