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Lelu [443]
3 years ago
14

Plz i want the answer

Mathematics
2 answers:
sineoko [7]3 years ago
6 0

X=5

y=2

then a: 3*5+2=17

b:2*5*5=50

c:5-2=3*3=9

a=17

b=50

c=9

densk [106]3 years ago
5 0

Answer:

Step-by-step explanation:

1. 3(5) plus 2 = 17

2. 2(5)^2 = 25(2) = 50

3. (5-2)^2 =3^2 = 9

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Solve the following equation: 12 x three eighths PLS HELPPP THIS IS THE 2ND TIME ASAP
mr_godi [17]

Answer:

12*3/8 we just turn the 12 into a improper fraction and multiply the top and the bottom with 3/8 top and bottom so

12/1*3/8

12*3=36

1*8=8

so 36/8 the answer is

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Hope This Helps!!!

8 0
3 years ago
Read 2 more answers
The correct answer is...?
Elanso [62]

<em>Answer:</em>

<em>The answer to both problems is </em><em><u>GRAPH</u></em>

<em>I hope this helps:)</em>

8 0
3 years ago
Harmons and Smiths are having a sale on apples. Harmons charges $1.25 for 5 apples. Smiths charges $2.04 for 6 apples. Find the
8090 [49]

Answer:

0.09

Step-by-step explanation:

Divide 1.25 by 5 which is 0.25, and 2.04 by 6 which is 0.34

Then subtract the answers 0.34-0.25=0.09

7 0
3 years ago
Which expression represents a<br> positive integer?<br> F. – 6²<br> H. (-5)<br> G. (-3)<br> 1.-23
marta [7]
F -6*-6 = 36 which is a positive interger
3 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
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