Answer:
C. w(2w + 5) = 50
Step-by-step explanation:
Given: A rectangle’s length is 5 inches more than twice its width.
Area (A) = 50 square inches.
Let "l" be the length of the rectangle and "w" be the width of the rectangle.
l = 5 + 2w (5 more than twice its width)
Area of a rectangle A = length * width
Now let's plug in A = 50 and l = 5 + 2w
50 = (5+ 2w)(w)
Which can be written as
w(2w + 5) = 50 [Using the commutative property of addition and multiplication]
Commutative property of addition: a + b = b + a
Commutative property of multiplication: a*b = b*a
The above equation is used to find the value of its width(w)
Therefore, the answer is C. w(2w + 5) = 50
