You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:
a² = b²+c²
As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:
b = √(a²-c²) b = √(10²-4²) b = 9.16
With these values, we can find the hypotenuse in the triangle "B": x = √b²+c² x = √(9.16)²+(4)² x = 10
Answer:
<h2>D) - 9/7</h2>
Hope this will help you lot.
Given, (0,−2).
Since the x-coordinate is 0, the point clearly lies on y-axis.
Also, the y-coordinate −2 being negative, the point lies on the negative y-axis.
Answer:
(-2, 3)
Step-by-step explanation:
A is translated from (5, 1) to A' at (6, -2).
That is, it moves <em>one unit to the right and three units down</em>.
B is also translated to B' one unit to the right and three units down to (-1, 0).
B must be <em>one unit to the left and three units above B'</em>.
Thus, the coordinates of B are (-2, 3).
The diagram below shows the translation of side AB of ∆ABC to its new location at A'B'.
