The hang time will be the same because the amount of time spent in the air is dependent on the vertical height. The fact that the player covers horizontal distance is simply due to him also pushing forward, instead of only upwards.
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
OBAN
92
|
| STANRAER
172-------------------------------------112
To read this table you have to draw a vertical from OBAN downward aa horizontal line from the 1st value of STANRAER. The intersection point show the number of miles.
So there are 172 miles & the consumption is 8 mi/gal,. He needs 172/8 gal.
Cost number of gallons needed x price/ gallon
COST = (172/8) x 0.83
COST = (21.5) x 0.83 = 17.845 ≈ $17.85 (1st answer)
B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks.
The table was <em><u>22.5 inches wide</u></em>.
hope this helps!
