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2 years ago

F (x) = v= - 8. Find f '(x) and its domain.

Mathematics

1 answer:

Flauer [41]2 years ago

5 0

Answer:

Step-by-step explanation:

Hope this helps

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2(x - 2) = -4x + 44 what does x equal

Komok [63]

2(x - 2) = -4x + 44

First, expand. / Your problem should look like: $2x - 4 = -4x + 44$
Second, add 4 to both sides. / Your problem should look like: $2x = -4x + 44 + 4$
Third, simplify -4x + 44 + 4 to get -4x + 48. / Your problem should look like: $2x = -4x + 48$
Fourth, add 4x to both sides. / Your problem should look like: $2x + 4x = 48$
Fifth, add 2x + 4x to get 6x. / Your problem should look like: $6x = 48$
Sixth, divide both sides by 6. / Your problem should look like: $x = \frac{48}{6}$
Seventh, simplify $\frac{48}{6}$ to 8. / Your problem should look like: $x = 8$

Answer: x = 8

5 0

2 years ago

Read 2 more answers

Is this an inequality or equation?

romanna [79]

Answer:

Equation

Step-by-step explanation:

A statement that the values of two mathematical expressions are equal (indicated by the sign =).

^^ This is the definition of equation

Difference in size, degree, circumstances, etc.; lack of equality.

^^ This is the definition for Inequality

The question moves more toward equation than inequality.

3 0

2 years ago

Read 2 more answers

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago

Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

6 0

2 years ago

Can someone give me this answer 15 points

Harrizon [31]

J is the correct answer

$180 - (90 + 20) = 180 - 110 \\ = 70$

good luck

3 0

2 years ago