Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
2**(32 - netmask) - 2 = number of nodes available
The netmask is in CIDR (Common Internet Domain Routing) notation, without the slash.
One of the nodes would be needed for a router or else you can't communicate with other networks.
Answer: Could be subdivided into smaller and smaller units.
Explanation:
The continuous data are basically measured in the small units and can be easily subdivided into smaller parts without changing their actual meaning.
The continuous data also contain numeric value and can be divided into smaller and finer meaningful parts.
The continuous data can be measured according to the precision of the system. The size and volume are the example of the continuous data.
