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Delvig [45]
3 years ago
5

The ________ view in access looks similar to an excel spreadsheet.

Computers and Technology
1 answer:
ch4aika [34]3 years ago
6 0
Datasheet 
<span>The datasheet view in access looks similar to an excel spreadsheet.</span>
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Sedbober [7]
Equal sign (=) 
hope so !!!

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What is the difference between a switch's physical interface and the vlan interface?
Andreyy89
<span>Switch's physical interface is something as the name itself suggests itself that it is a physical port to which you can plug in a cable or a wire based on its function and usage where as VLAN interface is no physical port but are created virtually when needed.</span>
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What is the common name for the growth rate function N?
kolezko [41]

Answer:

Linear.

Explanation:

The common name for the growth rate function N is linear.N growth rate is directly proportional to the input.So it grows linearly.It does not grow rapidly like other growth functions like quadratic,exponential and cubical.

Constant growth does not grow over time it stays as it is.

Hence the answer to this question is linear.

3 0
3 years ago
Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12
Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

   cout<<"Operator: ";

   cin>>ope;

   srand((unsigned) time(0));

   int num1 = rand() % 12;

   int num2 = rand() % 12;

   int result = 1;

   if(ope == 1){

       cout<<num1<<" + "<<num2<<" = ";

       result = num1 + num2;

   }

   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

       result = num1 * num2;

   }

   else{

       cout<<"Invalid Operator";

   }

   cin>>yourresult;

   if(yourresult == result){

       cout<<"Correct!";

   }

   else{

       cout<<"Incorrect!";

   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

6 0
3 years ago
In your own view, how can social media be used in teaching and learning in higher education?
g100num [7]

Answer:

through the use of zoom to teach.And reading books online

4 0
2 years ago
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