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steposvetlana [31]
3 years ago
10

Which of the following attack is a threat to confidentiality?

Computers and Technology
1 answer:
velikii [3]3 years ago
3 0

Answer:

The correct answer is letter "B": masquerading.

Explanation:

The attack referred to as masquerading simply consists of impersonating the identity of an authorized user of an information system. The impersonation could take place electronically -<em>the user has a login and password that does not belong to him to access a server</em>- or personally -<em>employees accessing restricted areas of a company.</em>

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8 0
2 years ago
Which of the following for-loop headers results in equivalent numbers of iterations: A. for (int q = 1; q &lt;= 100; q++) B. for
vladimir2022 [97]

Answer:

b

Explanation:

C and D have equivalent iterations

C:       D:

99    990

90      900

81      810

72      720

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8 0
3 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
3 years ago
Cell division is called:
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Answer:

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Explanation:

6 0
3 years ago
Write a program that calculates the occupancy rate for ahotel. The program should start by asking the user how many floorsthe ho
Oksana_A [137]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

using namespace std;   //to identify objects like cin cout

int main(){  //start of main function

       int MinFloors = 1;  //minimum number of floors

       int MinRooms  = 10; //minimum number of rooms

       int NoOfFloors;  //stores number of floors

       int NoOfRooms;  //stores number of rooms

       int OccupiedRooms;  //stores number of rooms occupied

       double TotalRooms=0, TotalOccupied=0;   //stores computed total number of rooms and total number of occupied rooms

       cout<<"How many floors does the hotel have? ";  //prompts user to enter number of floors

       do{  //iterates until the user enters valid number of floors

           cout<<"(cannot be less than "<<MinFloors<<"): ";  //error message

           cin >>NoOfFloors;  //reads number of floors from user

       }while(NoOfFloors<MinFloors);  //repeats as long as number of floors is less than minimum number of floors

       for(int floor=1; floor <= NoOfFloors; floor++){    //iterates through the floors to skip third iteration

           if(floor == 3){   //if floor is third floor

               continue;             }  

           cout<<"How many rooms are on floor " <<floor;  //prompts user to enter number of floors

           do{  //start of do while loop

               cout<<"(cannot be less than "<<MinRooms<<"): ";  //error message

               cin >>NoOfRooms;  //reads number of rooms from user

           }while(NoOfRooms<MinRooms);    //iterates as long as number of rooms are less than valid minimum number of rooms

           TotalRooms += NoOfRooms;   //adds number of rooms to the count of total number of rooms

           cout<<"How many of those rooms are occupied?";  //prompts user to enter number of rooms occupied

           do{  //start of do while loop

         cout<<"(cannot be less than 0 or greater than "<<NoOfRooms<<"): ";  //generates error message

         cin >>OccupiedRooms;  //reads number of rooms occupied by user

           }while(OccupiedRooms<0 || OccupiedRooms>NoOfRooms);   //iterates as long as the number of occupied rooms are less than 0 or greater than number of rooms

           TotalOccupied += OccupiedRooms;    }    //adds number of rooms occupied to the count of total number of occupied rooms    

       cout<<"\nThe hotel has a total of "<<TotalRooms<<" rooms"<<endl;  //displays the total number of rooms in the hotel

       cout<<TotalOccupied<<" are occupied."<<endl;  //displays the total number of occupied rooms

       cout<<(TotalRooms-TotalOccupied)<<" are unoccupied."<<endl;  //displays the total number of unoccupied rooms

cout<<"The occupancy rate is: "<<100*(TotalOccupied/TotalRooms)<<"%"<<endl;     }  //computes and displays the occupancy rate

   

Explanation:

The program first prompts the user to enter number of floors in the hotel. Lets say user enters 6. This is stored in NoOfFloors So

NoOfFloors = 6

So the loop runs for 6 times

Next it asks user to enter the number of rooms in the floor 1. Lets say user enters 12 so this is stored in NoOfRooms so

NoOfRooms = 12

TotalRooms += NoOfRooms;

this statement keeps adding number of rooms to TotalRooms so

TotalRooms = 12

Next program asks user about the number of occupied rooms. Lets say user enters 10 so this is stored in OccupiedRooms so

OccupiedRooms = 10

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10

At next iteration program asks user again to enter number of rooms in floor 2. Suppose user enters 14 so

NoOfRooms = 12

TotalRooms += NoOfRooms;

TotalRooms = 12+14

TotalRooms = 26

Program asks again to enter number of occupied rooms so it becomes:

OccupiedRooms = 8

this statement keeps adding number of rooms to TotalOccupied so

 TotalOccupied += OccupiedRooms;

TotalOccupied = 10+8

TotalOccupied = 18

Next is skips floor 3 and iteration 3. and asks user to enter number of rooms in floor 4. Suppose user enters 14

Number of rooms become:

TotalRooms = 12+14+14

TotalRooms = 40

and suppose user enters 14 as occupied rooms so total occupied become:

TotalOccupied = 10+8 + 14

TotalOccupied = 32

For floor 5: Suppose user enters 13

TotalRooms = 12+14+14+13

TotalRooms = 53

For floor 5: Suppose user enters 10

TotalOccupied = 10+8 + 14+10

TotalOccupied = 42

For floor 6: Suppose user enters 12

TotalRooms = 12+14+14+13+12

TotalRooms = 65

For floor 6: Suppose user enters 11

TotalOccupied = 10+8 + 14+10+11

TotalOccupied = 53

Now the loop breaks

Hence

TotalRooms = 65

TotalOccupied  = 53

total unoccupied = TotalRooms-TotalOccupied = 65-53 = 12

The occupancy rate is: 100*(TotalOccupied/TotalRooms) = 100*(53/65) = 81.5385

The output of the program is attached in a screenshot.

6 0
4 years ago
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