Answer:
I may be wrong but I think it is -1/32
Step-by-step explanation:
Answer:
hope it's help u
Step-by-step explanation:
Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
Answer: 300 square feet
Step-by-step explanation:
length of walkway = 20 + 2x
width of walkway = 15 + 2x
A(x) = (20 + 2x)(15 + 2x)
A(x) = 300 + 30x + 40x + 4x2
A(x) = 300 + 70x + 4x2
Answer:
׳+3ײ-72×-324
Step-by-step explanation:
I hope it help
