the answer is A ;
sin = opposite/ hypotenuse
= 24/ 26 ( we need to simplify it)
= 12/13
Answer:
15=2x
There are fifteen 1 blocks and two x blocks, which makes 15=2x(or 2x=15)
Answer:
10.4 to nearest tenth.
Step-by-step explanation:
If we draw lines from the centre of the circle to each vertex of the hexagon we get 6 equilateral triangles of side length 2.
Altitude of each triangle = sqrt(2^2 - 1^2)
= sqrt3.
So the area of 1 triangle = 1/2 * 2 * sqrt3
= sqrt3
Therefore the area of the hexagon = 6 * sqrt3
= 6sqrt3
= 10.3923
Answer:
The true statements are:
B. Interquartile ranges are not significantly impacted by outliers
C. Lower and upper quartiles are needed to find the interquartile range
E. The data values should be listed in order before trying to find the interquartile range
Step-by-step explanation:
The interquartile range is the difference between the first and third quartiles
Steps to find the interquartile range:
- Put the numbers in order
- Find the median Place parentheses around the numbers before and after the median
- Find Q1 and Q3 which are the medians of the data before and after the median of all data
- Subtract Q1 from Q3 to find the interquartile range
The interquartile range is not sensitive to outliers
Now let us find the true statements
A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)
B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>
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C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>
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D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)
E. The data values should be listed in order before trying to find the interquartile range ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>
