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vitfil [10]
3 years ago
8

What is 7 times as much as the sum of 1/3 + 4/5

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>
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If 3 is added to a number and multiplied the result by 5 gives 55 what is the number​
MakcuM [25]

Answer:24

Step-by-step explanation:Let the number we seek be X.

We are Given:

1). (5X+3 ) x (2) = 30

Expand and Rearrange.

(10X +6 ) = 30.

10X = 24.

2). X equals 2.4 . This is the answer for the number we seek.

Always check the answer.

This is Good Working Practice ALWAYS.

For Exams or similar remember:

Presentation (Neat & Tidy), Method & Layout (Show you understand), Accuracy.

All these count in most exams.

The first two points help greatly if your Answer is in error, but your METHOD Is CLEAR & CORECT.

Similarly, if the Check is wrong, mention this, but also, if the case, mention e.g. time ran out .. You may be credited as AWARE if your presentation and Method show you understood what to do and why.

CHECK: Substitute the answer for X into the original equation 1).

Equn. 1). (5X +3)*2 = 30.

Put in the value for X. Expand & Re-arrange.

(( 5 ).( 2.4 ) + ( 3 ).( 2 ) = 30.

( 12 + 6 ) = 30.

24 = 24. Checked & Agreed.

That’s about it.

6 0
3 years ago
I need to find sec(theta)= 2(sqrt3)/3
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sec θ = \frac{2\sqrt{3}}{3}

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cos θ = \frac{3}{2\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}})

cos θ = \frac{3\sqrt{3}}{3*2}

cos θ = \frac{\sqrt{3}}{2}

Look at the Unit Circle to see that cos = \frac{\sqrt{3}}{2} at 30° and 330°  ( which is equivalent to π/6 and 11π/6)


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Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.

Step-by-step explanation:

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