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vitfil [10]
3 years ago
8

What is 7 times as much as the sum of 1/3 + 4/5

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>
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68.76 rounded to the nearest whole number
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Find the area of the shaded region
dsp73

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Step-by-step explanation:

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If 5a=-4b+5 and 3a=-2b+3, what is 6b?
Misha Larkins [42]
There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
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a = 1
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6 0
3 years ago
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4 0
3 years ago
Read 2 more answers
Zubin has two pieces of string. One piece is 36 inches long and the other is 48 inches long. He wants to cut them into equal pie
skelet666 [1.2K]

Answer:

12 pieces each:

S_1 = 3\ in

S_2= 4\ in

Step-by-step explanation:

Given

S_1 = 36\ in -- first string

S_2 = 48\ in --- second string

Required

Determine the number of equal pieces

To do this, we first calculate the HCF of the length of both pieces (36\ and\ 48)

36 = 2 * 2 * 3 * 3

48 = 2 * 2 * 2 * 2 * 3

Common\ prime\ factors = 2, 2\ and\ 3

The HCF is:

HCF = 2 * 2 * 3

HCF = 12

<em>Hence, he can cut both strings to 12 pieces each</em>

<em></em>

<em>Recall that </em>

S_1 = 36\ in

<em>The first string can then be cut in to 3 inches each (i.e. 36/12)</em>

S_2 = 48\ in

<em>The first string can then be cut in to 4 inches each (i.e. 48/12)</em>

7 0
3 years ago
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