There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best: 5a = -4b + 5 3a = -2b + 3 You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So: 5a = -4b +5 6a = 4b +6 Add both equations together. 11a = 11 a = 1 Plug in the a value into any of the previous equations: 5(1) = -4b + 5 -4b = 0 b = 0 So, since we know that b = 0, 6b is also 0.
