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Alinara [238K]
3 years ago
8

Ethnic groups do not originate in a specific location.

Geography
2 answers:
Degger [83]3 years ago
5 0
The answer is False because ethnic groups do not originate in a specific location
VLD [36.1K]3 years ago
4 0
The answer is False
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Desertification in the region is due to _____. agriculture deltas cataracts overgrazing population growth user: the intertropica
Goshia [24]
I think the correct answers from the choices listed above are overgrazing and control river currents, respectively.

 <span>Desertification in the region is due to large petroleum deposits. 

</span><span> The intertropical convergence zone control river currents.

Hope this answers the question. Have a nice day. </span>
6 0
3 years ago
One of the earliest astronomical CCDs had 160,000 pixels, each recording 8 bits (256 levels of brightness). Today's CCDs may con
Ilia_Sergeevich [38]

Answer:

10000 times more data

Explanation:

Data recorded by earlier astronomical CCD's = (pixel× bit/pixel)

160,000×8 = 128,0000

Data recorded by new astronomical CCD= (pixel× bit/pixel)

= 10^9×15= 15×10^9

comparison = \frac{15\times10^9}{128\times10^4}

= 11718.75

Which means nearly 10000 times more data

4 0
4 years ago
Read 2 more answers
Which of the following is not an example of a dictator
zalisa [80]
I believe the answer would be A-Queen Elizabeth I was a monarch, but not a dictator.
4 0
3 years ago
What mountains are between spain and france?
finlep [7]
The Pyrenees mountain chain
7 0
3 years ago
Wasp-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. how many au from the star i
kaheart [24]
To solve this problem we will use Kepler's third law of planetary motion. Formula for that law is:
T^{2} = \frac{4  \pi ^{2} }{GM}  a^{3}
Where:
T = orbital period
G = universal gravitational constant
M = mass of star
a = distance from planet to star

By rearranging this formula we get:
\frac{T^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM}
For Earth we have:
\frac{365^{2}}{1^{3} } = \frac{4 \pi ^{2} }{GM}
For Wasp-32b we have:
\frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{G*1.1M} or
1.1* \frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM} 

We can see that right sides are same. Left sides must be same. We can use this to solve for distance.
\frac{365^{2}}{1^{3} } = 1.1* \frac{2.7^{2}}{a^{3}
\frac{365^{2}}{1.1* 2.7^{2}} = \frac{1}{a^{3} } \\ \\ 2.7^{2} =365^{2}*a^{3} \\ \\ a^{3} =\frac{2.7^{2} }{365^{2}} \\ \\ a= \sqrt[3]{\frac{2.7^{2} }{365^{2}} } \\ \\ \\ a=0.038AU

Wasp-32b is at distance of 0.038AU.
8 0
3 years ago
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