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PtichkaEL [24]
3 years ago
9

Nathan has three pieces of wood the first is 9.8 feet in length the second is 7.5 feet in length and the third is 12 feet in len

gth he uses 5.2 feet fromthe first pieces and 6.1 feet from the second piece he does not use the third piece of wood how many feel of wood does nathan not use
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

17.7

Step-by-step explanation:


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3 years ago
In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre
Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that p = 0.09

41 people arrested for DUI in Illinois are selected at random.

This means that n = 41

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

E(X) = np = 41*0.09 = 3.69

d. What is the standard deviation of the number of repeat offenders?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83

4 0
2 years ago
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