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Liula [17]
4 years ago
6

Which statement about credit for CLEP exams is accurate? A. Students who fail a course can take a CLEP exam to earn credit for t

hat course. B. Students aren't given credit for an exam unless they earn a perfect score. C. Credit for an exam typically equals what students enrolled in the course would earn. D. Students enrolled in a course can take a CLEP exam instead of the final to earn credit for the course.
SAT
2 answers:
Elanso [62]4 years ago
6 0
<span>C. Credit for an exam typically equals what students enrolled in the course would earn.
       CLEP stands for College Level Examination Program. Which is a series of tests in different subject areas to determine if the person being examined has the equivalent knowledge of the subject that a typical student in college would gain after taking a class in that subject. CLEP is quite useful for advanced students to skip pass introductory classes. By taking a CLEP and passing the CLEP, a student will generally save quite a bit of money since tuition for the actual class doesn't need to be spent and will save the time that the student would have had to spend taking the class. With that in mind, let's look at the options and see what does and does not make sense.
       A. Students who fail a course can take a CLEP exam to earn credit for that course. * This is actually true, but to honest, it's highly unlikely that a student who failed the course would actually pass the CLEP. So this is a bad choice.
       B. Students aren't given credit for an exam unless they earn a perfect score. * Nobody's perfect and the CLEP doesn't expect you to be perfect. Just be good enough. Just like college doesn't require a 4.0 GPA, CLEP doesn't require a perfect score. So this is a bad choice.
       C. Credit for an exam typically equals what students enrolled in the course would earn. * This is exactly correct. One of the major reasons for taking a CLEP is to bypass introductory classes to various subjects. The $85 for the CLEP exam is a lot cheaper and faster than the close to $1000 average for a college class. This is the correct choice.
       D. Students enrolled in a course can take a CLEP exam instead of the final to earn credit for the course. * You could do this, but it's rather silly since the CLEP is very much like the final exam in a college class. And since you've spent the time in class, why spend an extra $85 to effectively take the same type of exam? So this is a bad choice.</span>
monitta4 years ago
6 0
The secondary answer to this question would be "Students are responsible for requesting score reports for colleges and employers" (APEX)
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Amanda travels to work from home in 60
vodomira [7]

Answer:

50 minutes

Explanation:

We can set this up as a rate * time = distance problem. We can set the rate at which Amanda travels to work to be x, since that quantity is unknown. The time it takes is given to be 60 minutes. This means that the total distance she travels to get to work is 60x. On the other hand, the way back home has more unknown quantities. The exact rate is unknown, but we do know that it is 20% more than the rate at which Amanda travels to work. This means that the rate is x + .20x, or 1.2x. We can set the time to be y, which means the total distance she travels to get back home is 1.2xy. We are told that Amanda uses the same route to get to and from work, which means 60x = 1.2xy. All we have to do now is solve this equation:

60x=1.2xy\\60=1.2y\\y=50

If we divide through by x and then isolate y, we get that it takes Amanda 50 minutes to get home

4 0
2 years ago
Use the information above and the trigonometric identities to prove that Asin(wt
jenyasd209 [6]

Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) =  Asin(ωt + φ)

<h3>How to prove Trigonometric Identities?</h3>

We know from sum and difference identities that;

sin (α + β) = sin(α)cos(β) + cos(α)sin(β)

sin (α - β) = sin(α)cos(β) - cos(α)sin(β)

c₂ = Acos(φ)

c₁ = Asin(φ)

The Pythagorean identity can be invoked to simplify the sum of squares:

c₁² + c₂² =

(Asin(φ))² + (Acos(φ))²

= A²(sin(φ)² +cos(φ)²)

= A² * 1

= A²

Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us;  Asin(ωt + φ)

Complete Question is;

y(t) = distance of weight from equilibrium position

ω = Angular Frequency (measured in radians per second)

A = Amplitude

φ = Phase shift

c₂ = Acos(φ)

c₁ = Asin(φ)

Use the information above and the trigonometric identities to prove that

Asin(ωt + φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Read more about Trigonometric Identities at; brainly.com/question/7331447

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8 0
2 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
ICE Princess25 [194]

Answer:

The answer is 1.

Explanation: I just got it on Edge.

4 0
3 years ago
Read 2 more answers
Convert the following complex number into its polar representation -4i
maks197457 [2]

The expression which represent the polar form of complex number -4i when converted into the polar form is 4(cos π+ isin π)

<h3>What is complex number?</h3>

A complex number is the combination of real and imaginary number. In a complex number, real part and imaginary part of number is written together. For example,

a+bi

Here, (a) is the real part while (b) is the imaginary part.

The complex number which need to convert into its polar representation is,

n=-4i

It can be rewritten as,

n=0-4i

The radius r of the polar form is,

r²=0²+(-4)²

r²=0+16

r=4

The value of cos theta is,

tan θ=0/-4

θ=tan⁻¹(0)

θ=π

Thus, the polar form is,

z=rcos θ+(r sin θ)i

z=-4(cos π+ isin π)

Thus, the expression which represent the polar form of complex number -4i when converted into the polar form is 4(cos π+ isin π)

Learn more about the complex number here;

brainly.com/question/2218826

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4 0
3 years ago
If you can add or subtract which ones faster
Nuetrik [128]

Answer:

addition

Explanation:

in my opinion iiiikki

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3 years ago
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