Answer:
269
Step-by-step explanation:
The margin of Error is E = 0.05
The level of significance is, α = 1 - confidence level = 1 - 0.9 = 0.1
Assume that the proportion is, p =0.5
From the standard normal table, observe that the critical value of Z for two tail test and 10% level of significance is 1.64
The calculation of sample size is as follows: n = (Z/E)²p(1-p)
n = (1.64/0.05)²0.5 (1 - 0.5)
n = (1.64/0.05)² 0.25
n = 1075.84 × 0.25
n = 268.96 ≈ 269
The required sample size with the given margin of error approximately is 269. This value indicates the size of the customers who are using this company’s products.
1/2, 4/8, etc. Because they all equal to one half. <span />
790 students I subtracted 1495-85 then divided that by two then added the 85 to 705 to get 790
