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Bumek [7]
3 years ago
9

If you add 20% of a number to the number itself what percent of the result would you have to subtract

Mathematics
1 answer:
Alina [70]3 years ago
5 0
N+ 0.2n = 1.2nn = (1.2n) - (1/6)*(1.2n)
1/6 = 16.667%
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A stainless steel garbage can is in the shape of a right circular cylinder if its radius is 6 inches and it's volume is 864 pi i
tamaranim1 [39]
\bf \textit{volume of a cylinder}=V=\pi r^2h\qquad 
\begin{cases}
r=radius\\
h=height\\
-----------\\
r=6\ in\\
V=864\pi \ in^3
\end{cases}
\\\\\\
V=\pi r^2h\implies 864\pi =\pi (6)^2h\impliedby \textit{solve for "h"}
6 0
3 years ago
25. Find the area of the trapezoid. Leave your answer in simplest radical form. The figure is not drawn to scale.
n200080 [17]

Answer:

Option D. 44\ cm^{2}

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

A=\frac{1}{2}[b1+b2]h

we have

b1=8\ cm

b2=(4+8+2)=14\ cm

h=4\ cm

substitute the values

A=\frac{1}{2}[8+14](4)=44\ cm^{2}

6 0
2 years ago
a circle has a radius of 7ft. Find the radian measure of the central angle 0 that intyercepts an arc of length 16ft
Iteru [2.4K]

Answer:

2.29 rads

Step-by-step explanation:

The  length of the arc of a circle of radius r is given by;

l = rθ            ---------------------------(i)

Where;

l = length of the arc

θ = central angle o that intercepts that arc and measured in radians.

From the question:

l = 16ft

r = 7ft

Substitute these values into equation (i) as follows;

16 = 7θ

Make θ subject of the formula

θ = \frac{16}{7}

θ = 2.29    

Therefore, the radian measure of the central angle is 2.29 rads

8 0
3 years ago
According to an NRF survey conducted by BIGresearch, the average family spends about $237 on electronics (computers, cell phones
Usimov [2.4K]

Answer:

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is 0.0537.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is 0.0023.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is 0.1101.

Step-by-step explanation:

We are given that according to an NRF survey conducted by BIG research, the average family spends about $237 on electronics in back-to-college spending per student.

Suppose back-to-college family spending on electronics is normally distributed with a standard deviation of $54.

Let X = <u><em>back-to-college family spending on electronics</em></u>

SO, X ~ Normal(\mu=237,\sigma^{2} =54^{2})

The z score probability distribution for normal distribution is given by;

                                 Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean family spending = $237

           \sigma = standard deviation = $54

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is = P(X < $150)

        P(X < $150) = P( \frac{X-\mu}{\sigma} < \frac{150-237}{54} ) = P(Z < -1.61) = 1 - P(Z \leq 1.61)

                                                             = 1 - 0.9463 = <u>0.0537</u>

The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9463.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is = P(X > $390)

        P(X > $390) = P( \frac{X-\mu}{\sigma} > \frac{390-237}{54} ) = P(Z > 2.83) = 1 - P(Z \leq 2.83)

                                                             = 1 - 0.9977 = <u>0.0023</u>

The above probability is calculated by looking at the value of x = 2.83 in the z table which has an area of 0.9977.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is given by = P($120 < X < $175)

     P($120 < X < $175) = P(X < $175) - P(X \leq $120)

     P(X < $175) = P( \frac{X-\mu}{\sigma} < \frac{175-237}{54} ) = P(Z < -1.15) = 1 - P(Z \leq 1.15)

                                                         = 1 - 0.8749 = 0.1251

     P(X < $120) = P( \frac{X-\mu}{\sigma} < \frac{120-237}{54} ) = P(Z < -2.17) = 1 - P(Z \leq 2.17)

                                                         = 1 - 0.9850 = 0.015

The above probability is calculated by looking at the value of x = 1.15 and x = 2.17 in the z table which has an area of 0.8749 and 0.9850 respectively.

Therefore, P($120 < X < $175) = 0.1251 - 0.015 = <u>0.1101</u>

5 0
3 years ago
Which set is a subset of every set? {1} {} {0}
Galina-37 [17]
Answer: The empty set
The empty set is a subset for every set.
3 0
2 years ago
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