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2 answers:
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Answer:
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the population = 500 </em>
<em>Given standard deviation of the Population = 75</em>
Let 'X' be the variable in normal distribution
<em>Given X = $410</em>
<em></em><em></em>
<u><em>Step(ii):-</em></u>
The probability that a family spends less than $410 per month
P( X < 410) = P( Z < - 1.2 )
= 0.5 - A( -1.2)
= 0.5 - A(1.2)
= 0.5 - 0.3849 ( ∵from normal table)
= 0.1151
<u>Final answer:-</u>
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Answer: a) 0.9961, b) 0.9886
Step-by-step explanation:
Since we have given that
Probability that does not show up = 0.10
Probability that show up = 0.90
Here, we use "Binomial distribution":
n = 125 and p = 0.90
Number of passengers that hold in a flight = 120
a) What is the probability that every passenger who shows up can take the flight?
(b) What is the probability that the flight departs with empty seats?
Hence, a) 0.9961, b) 0.9886