Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
150 x - 80 y + 50 - 50 x - 25 y + 20
<em><u>Arranging </u></em><em><u>like </u></em><em><u>terms </u></em>
150 x - 50 x -25 y - 80y + 50 + 20
100x - 105 y + 70
<h3>5 ( 20x - 21y + 14) </h3>
im not sure but its either A Or D
Step-by-step explanation:
because the points are on that point
r = 255
r = R-2RF/W
R = 1,750
F = 63.2
W = 148
Now, we need to plug the values in to substitute the variables with real numbers.
r = 1750-2(1750 x 63.2)/148
First, solve for the parentheses.
r = 1750-2(110600)/148
Second, multiply by 2.
r = 1750-221200/148
Next, divide by 148.
r = 1750 - 1494.594
Then, we subtract.
r = 255.406
Lastly, we round it to the nearest whole number.
r = 255
