<em>y</em> - 1/<em>z</em> = 1 ==> <em>y</em> = 1 + 1/<em>z</em>
<em>z</em> - 1/<em>x</em> = 1 ==> <em>z</em> = 1 + 1/<em>x</em>
==> <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)
<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1
==> 2<em>x</em> ² - 1 = 2<em>x</em> + 1
==> 2<em>x</em> ² - 2<em>x</em> - 2 = 0
==> <em>x</em> ² - <em>x</em> - 1 = 0
==> <em>x</em> = (1 ± √5)/2
If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.
He overall had a 10% loss.
In order to find the number of chips that would result in the minimum cost, we take the first derivative of the given equation. Note that the derivative refers to the slope of the graph at a given point. We can utilize this concept knowing that at the minimum or maximum point of a graph, the slope is zero.
Taking the derivative of the given equation and equating it to zero, we have:
y' = (0.000015)(2)x - (0.03)x° + 0
0 = (0.00003)x - 0.03
Solving for x or the number of chips produced, we have x = 1000. We then substitute this value in the given equation, such that,
y = (0.000015)(1000)² - (0.03)(1000) + 35
The minimized cost, y, to produce 1000 chips is then calculated to be $20.
h = 50 cos ( pie(x - 10 )/15 ) + 52
80 = 50 cos ( pie( x - 10 )/15 ) + 52
80 - 52 = 50 cos ( pie( x - 10 )/15 )
28 = 50 cos ( pie( x - 10 )/15 )
cos ( pie( x - 10 )/15 ) = 28/50
cos ( pie( x - 10 )/15 ) = 56/100
cos ( pie( x - 10 )/15 ) = cos ( 56 )
cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )
Thus ;
pie( x - 10 )/15 = 0.3111 pie
( x - 10 )/15 = 0.3111
x - 10 = 15 × 0.3111
x - 10 = 4.6665
x = 10 + 4.6665
x = 14.6665 [ approximately ]
Thus the correct answer is exactly what u chose goodjob .....
6 and 10 because 6 times 10 is 60 and 6 plus 6 plus 20 plus 10 is 32
