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3 years ago

F(x) = 2x^2 what is f(3)

Mathematics

2 answers:

katrin2010 [14]3 years ago

5 0

Answer:

18 since f(3)=18

Step-by-step explanation:

f(x)=2x^2 is give as our function. To find f(3) we need to replace x with 3.

f(3)=2(3)^2 (Replaced x with 3.)

f(3)=2(9) (Did 3^2 which was 3*3=9)

f(3)=18 (Did 2(9) which was 18)

egoroff_w [7]3 years ago

4 0

$f(3)=2\cdot 3^2=18$

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aksik [14]

Answer:

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4) 94º

Step-by-step explanation:

let 3 be x

let 1 be y

let 2 be z

let 4 be j

180=86+38+x 56=x

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3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

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3 years ago

Solve the proportion. 4 y = 7 ? y =

Leni [432]

Answer:

y=28/5

Step-by-step explanation:

Okay so for this we can use cross- multiplication. Basically, the product of the numerator of the first number and the denominator of the second is equal to the product of the denominator of the first and the numerator of the second.

What I mean is: 4*7=5*y

so,

28=5y

y=28/5

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3 years ago