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Helen [10]
3 years ago
15

Find the slope of the line that passes through (-4, 7) and (-6, -4)

Mathematics
2 answers:
klio [65]3 years ago
7 0

Answer:

m=\frac{11}{2}

Step-by-step explanation:

Kitty [74]3 years ago
4 0

Answer:

The slope of the line is 11/2

remember, rise over run.

Step-by-step explanation:

May I have brainliest please? :)

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The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

3 0
3 years ago
Read 2 more answers
The ratio of vowels to Constance to a paragraph is 3:5 there are 280 letters in the paragraph how many are vowels how many are c
Bas_tet [7]

Answer:

280/8 = 35 "sets"

35*3 = 105 Constance

35*5 = 175 vowels

Step-by-step explanation:

8 0
3 years ago
What is 2 and negative three using integers​
Darina [25.2K]

If you mean "how to write the sum", the answer is

2+(-3)

The result of this sum is -1, because you start from 2 on the number line and take 3 steps to the left (negative integers mean going left, positive integers mean going right)

4 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
100 POINTS HURRY
AnnyKZ [126]
Answer: is in the picture

8 0
3 years ago
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