y=-2x^2+2x+2 first isolate the x terms y=(-2x^2+2x)+2 undistribute the coefieicne infont of x^2 term y=-2(x^2-x)+2 take 1/2 of -1 and square it (-1/2 sqared=1/4) add negative and positive inside y=-2(x^2-x+1/4-1/4)+2 complete the square y=-2((x-1/2)^2)-1/4)+2 y=-2(x-1/2)^2+1/2+2 y=-2(x-1/2)^2+2.5
in form y=a(x-h)^2+k vertex=(h,k) y=-2(x-1/2)^2+2.5 vertex is (0.5,2.5)
for x=6 input 6 for x and evaluate y=-2(6)^2+2(6)+2 y=-2(36)+12+2 y=-72+14 y=-58
for x=6, the value is -58
the vertex form is y=-2(x-1/2)^2+2.5 vetex is (0.5,2.5)