Answer:
Part a) <1=72°
Part b) <2=108°
Part c) <3=72°
Part d) <4=108°
Step-by-step explanation:
step 1
Find the measure of angle 1
we know that
<1+108°=180° -----> by supplementary angles
so
<1=180°-108°=72°
step 2
Find the measure angle 2
we know that
<2=108° -----> by corresponding angles
step 3
Find the measure angle 3
we know that
<3=<1-----> by corresponding angles
so
<3=72°
step 4
Find the measure angle 4
we know that
<4=108° -----> by alternate exterior angles
3days=3chapters so he would have to read for 8 days
The answer is (-∞.∞).
Draw out a number line. Plot 0 and -4 on the number line.
Shade to the left of x = 0, and have a filled in circle at the endpoint. This is the graph of x≤0
Then graph x ≥−4 by plotting a filled in circle at -4, and shading to the right.
Note how the two graphs overlap to cover the entire real number line
So if we have x≤0 or x≥−4 then we're basically saying x is any real number. To write this in interval notation, we write (−∞,∞)
This is the interval from negative infinity to positive infinity (or just infinity). We exclude each endpoint because we can't actually reach infinity itself. Infinity is not a number. Infinity is a concept
Side note: if you change the "or" to "and", then the solution to x≤0 and x≥−4 would be [-4, 0][−4,0] to indicate the interval from x = -4 to x = 0, including both endpoints. This is the region where the two graphs overlap.
To know more about graphs
visit-:brainly.com/question/10712002
SPJ9
This is exponential growth/decay type problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case I=1250 and r=(1-.045)=0.955 so
F=1250(.955)^t and we want to find t for when F=800
800=1250(.955)^t
.64=.955^t take the natural log of both sides...
ln.64=t ln.955
t=(ln.64)/ln.995
t≈9.69 weeks
t≈9.69 weeks (to nearest hundredth of a week)