What is 1/2×( 3y)(4z)
1 answer:
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Answer:
Part A)
The number of marbles that Su has at the beginning is
The number of marbles that Bertha has at the beginning is
Part B)
The number of marbles that Su has at the end is
The number of marbles that Bertha has at the end is
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
----> equation A
----> equation B
substitute equation A in equation B
Find the value of x
Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is
The number of marbles that Bertha has at the beginning is
Part B) How many did they EACH have at the end?
so
therefore
The number of marbles that Su has at the end is
The number of marbles that Bertha has at the end is